If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x^2-60x+10=0
a = 9; b = -60; c = +10;
Δ = b2-4ac
Δ = -602-4·9·10
Δ = 3240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3240}=\sqrt{324*10}=\sqrt{324}*\sqrt{10}=18\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-18\sqrt{10}}{2*9}=\frac{60-18\sqrt{10}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+18\sqrt{10}}{2*9}=\frac{60+18\sqrt{10}}{18} $
| -23+2a=-7-8(10a+2) | | 4m+9=-4 | | 3z-3z+6z=12 | | 10/k=40/4 | | 4a+13a+-15a=-16 | | 4(3m+6)=-2(6m+2) | | 5n-40=2n-13 | | 18x-8=4(5x+1) | | -7b+20=13 | | 55=m+23 | | 8(-7+k)+k=6k-32 | | 7x-12+12x+24=180 | | -3w+6=-2-2w | | v/14+1=2 | | 8a-4a-2a+2a=4 | | 2k-7=k | | (3x+(-5))/2=11 | | 2j-j=19 | | 2x-5x+7=25 | | g(6)=3|12| | | -49-5m=-4(2m+7) | | 2+-2v=-8 | | -3=4+b/5 | | g/7+3=14 | | -7+5r=4r | | 3y+2+2y=17 | | x²+6x-832=0 | | 5m-6-8m=-7(4m+8) | | 11(2x)=110 | | -4+10(4m-7)=8-m | | 9t=10t-2 | | 14=r1.4 |